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在DolphinDB中使用时间函数datehour()遇到的一个问题

在DolphinDB的GUI中执行下述语句:

datehour(2018.09.03 8:30:00)

返回如下错误:

2020.12.09 17:14:24.420: executing code ...
Both arguments of 'pair' must be a scalar

请问哪里不对?


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使用datehour时间函数时,参数中的月、日、小时、分、秒都必须填满两位。
正确代码:

datehour(2018.09.03 08:30:00)

返回:

2018.09.03T08

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